Question

8. Observe the figure showing the path of abody which started from A and moved to C through B

a) Calculate the speed of the body?
b) What is the velocity of the body
c) What is the velocity of the body if it has taken 5 sec to reach a back from C
d) Compare the velocity of the body when it reached C from A and also When it reached
A and C

Answer 1

Given :

Mass first body (M1) = 2 kg

Kinetic energy of first body (K.E1) = 8 J

Mass of Second body (M2) = 4 kg

To FinD :

Kinetic Energy of 2nd body

SolutioN :

We are given that both the bodies are moving with same velocities,

For 1st Body :

⇒K.E1 = ½M1V²

⇒8 = ½ * 2 * V²

⇒8 = V²

⇒V² = 8

⇒V = √8

⇒V = 2√2

∴ Velocity of bodies is 2√2 m/s.

________________________

Now, Kinetic Energy of 2nd Body :

⇒K.E2 = ½M2V²

⇒K.E2 = ½ * 4 * (2√2)²

⇒K.E2 = 2 * 8

⇒K.E2 = 16

∴ Kinetic Energy of 2nd body is 16 J.

Answer 2

Refer the above attachment

Hope it helps