Question

8(p+2)-3[{(3-2p) -3(-3p-5)}]=0

Answer 1

$<b > Ello!¡$

Here's your answer

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Given : 8 ( p + 2 ) - 3 { ( 3 - p ) - 3 ( - 3p - 5 ) } = 0

• To find the value of p

Now ,

8 ( p + 2 ) - 3 { ( 3 - p ) - 3 ( - 3p - 5 ) } = 0

8p + 16 - 3 { 3 - p + 9p + 15 } = 0

8p + 16 - 3 ( 8p +18 ) = 0

8p + 16 - 24p - 54 = 0

- 16p - 38 = 0

- 16p = 38

- p = 38 / 16

p = - 19 / 8 [ ★ Required answer ]

So , the value of p is - 19 / 8

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Hope it helps!!

Answer 2

Answer:

8p+16-3[{3-2p+9p+15}]=0

8p+16-3[7p+18]=0

8p+16-21p-54=0

-13p-38=0

-13p=38

p=-38/13