Question

8 particles are situated at the corners of a cube of side a. Find out gravitational potential energy

Answer 1

Answer:

hey dear ,...

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For a mass of

m

potential energy of a test mass at distance r is given as

(

G

⋅

m

r

)

Total potential energy of the system is

G

m

2

l

×

4

+

2

⋅

G

m

2

√

2

l

or,

4

G

m

2

l

+

√

2

G

m

2

l

( Due to

4

mass at the vertices and 2 diagonally present,length of diagonal is

√

2

l

)

Distance of each mass from the centre is =length of diagonal/2 i.e

l

√

2

So,potential energy at the centre for 4 such mass is

⎛

⎜

⎝

G

m

l

√

2

⋅

4

⎞

⎟

⎠

i.e

4

√

2

G

m

l

$\huge\mathfrak\red{thanks}$

Answer 2

Answer:

hey dear ....

gravitational potential energy= g[q1q2]\r2