Question

8
Parveen wanted to make a temporary shelter for her car, by making a box-like structure
with tarpaulin that covers all the four sides and the top of the car (with the front face
as a flap which can be rolled up). Assuming that the stitching margins are very small,
and therefore negligible, how much tarpaulin would be required to make the shelter of
height 2.5 m, with base dimensions 4 mx 3 m?
for CI​

Answer 1

Answer:

Dimension of the non-like structure = 4m×3m×2.5m

Tarpaulin only required for all the

for sides and top.

Thus Tarpaulin required = 2(l+b)×h+lb

=[2(4+3)×2.5+4×3]m

2

=[35+12]m

2

=47m

2

Answer 2

Dimensions of the shelter

L =4m

B = 3m

h = 2.5m

Required area of the trapaulin to make the shelter = Area of four sides+ area of the top of the car

trapaulin required = 2 (l+b)×h+lb

=[2(4+3)×2.5+4×3]

=(35 + 12)

47msquare...