8 pipes are required to fill a tank in 1 hour 20
minutes. How long will it take if only 5 pipes of
the same type is used?
Answers
Answered by
35
8 pipes are required to fill a tank in 1 hour 20
minutes. How long will it take if only 5 pipes of
the same type is used?
⊙1 hr and 20 mins will be 80mins⊙
So 8 pipes take 80 mins to fill a tank.
The more number of pipes, the less time it takes to fill a tank. In this case, the tank is a constant as there is only 1 tank needed to be filled.
y=k/x
let y be time
let x be number of pipes
80=k/8
k= 80(8)
k= 640
y=640/5
y= 128 mins
y= 2hr 8mins
Answered by
28
Question :-
- 8 pipes are required to fill a tank in 1 hour 20minutes. How long will it take if only 5 pipes ofthe same type is used?
Given :-
- 8 pipes are required to fill a tank in 1hour 20minutes.
To find :-
- How long will it take if only 5 pipes of the same type is used?
Solution :-
Let the desired time to fill the tank be x minutes.
In 80 mins a tank is filled by 8 pipes
Lesser the number of pipes more will be the time required by it to fill the tank.
So, this is a case of inverse proportion.
Thus, the time is taken to fill the tank by 5 pipes is 128 minutes or 2 hour 8 minutes.
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