8 pipes are required to fill a tank in 2 hours. How long will it take if 6 pipes are used
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Answered by
0
Answer:
96 minutes
Explanation:
Let the desired time to fill the tank be x minutes.
In 80 mins a tank is filled by 6 pipes
Lesser the number of pipes more will be the time required by it to fill the tank.
So, this is a case of inverse proportion.
Hence, 80×6=x×5
⇒ 5 80×6 =x
⇒x=96
Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.
Hope it helps...
Answered by
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One pipe can fill in = 8*2=16
Fie can fill in = 16/5 hr or 3hr 20mins
mark my answer as brainliest
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