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From Chemical Kinetics
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C2H4O → CH4 + CO
at t = 0
pressure of C2H4O = 80 mm
at t = ending time ,
total pressure = 120 mm
pressure of C2H4O + pressure of CH4 + pressure of CO2 = 120 mm
(80 -x) + x + x = 120
80 + x = 120
x = 40mm
hence,
pressure of C2H4 , CO2, CH4 = 40 mm
now,
for 1st order reaction ,
t =1/K lna/( a - x)
K = 1/20 ln80/40
=ln2/20
now, half life of this reaction ,
T½ = ln2/K
= ln2/(ln2/20) = 20min
at t = 0
pressure of C2H4O = 80 mm
at t = ending time ,
total pressure = 120 mm
pressure of C2H4O + pressure of CH4 + pressure of CO2 = 120 mm
(80 -x) + x + x = 120
80 + x = 120
x = 40mm
hence,
pressure of C2H4 , CO2, CH4 = 40 mm
now,
for 1st order reaction ,
t =1/K lna/( a - x)
K = 1/20 ln80/40
=ln2/20
now, half life of this reaction ,
T½ = ln2/K
= ln2/(ln2/20) = 20min
abhi178:
i hope this will correct
yes ur answer is correct as per the option given in the book .... Thnx for d solution
d , is this possible ???
i meant thanks for the solution ur final answer is correct
the option given in the book is (c)
I didn't know how to solve this problem, therefore i m thankful for ur answer
ohh , thank dear !!!
xD
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