Question

8 rationalise
denominators 1/(√5 - 3)


1 /√5+√3​

Answer 1

Answer:

Answers are given below....

Step-by-step explanation:

$\frac{1}{\sqrt5-3}\\\\=\frac{1}{\sqrt5-3}*\frac{\sqrt5+3}{\sqrt5+3}\\\\=\frac{\sqrt5+3}{\sqrt5^2-3^2}\\\\=\frac{\sqrt5+3}{5-9}\\\\=\frac{\sqrt5+3}{-4}=\frac{-3-\sqrt5}{4}$

$\frac{1}{\sqrt5+\sqrt3}\\\\=\frac{1}{\sqrt5+\sqrt3}*\frac{\sqrt5-\sqrt3}{\sqrt5-\sqrt3}\\\\=\frac{\sqrt5-\sqrt3}{\sqrt5^2-\sqrt3^2}\\\\=\frac{\sqrt5-\sqrt3}{5-3}\\\\=\frac{\sqrt5-\sqrt3}{2}$

Hope it helps!

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