Question

8. समीकरण का केवल मूल-स
(i) 4r2 =1​

Answer 1

Answer :

• 4r² = 1

$\sf : \implies r^2 = \dfrac{1}{4}$

$\sf : \implies r = \sqrt{\dfrac{1}{4}}$

$\sf : \implies r = \sqrt{\dfrac{(1)^2}{(2)^2}}$

$\sf : \implies r = \sqrt{\Bigg(\dfrac{1}{2}\Bigg)^2}$

$\sf : \implies r = \dfrac{1}{2}$

Hence, value of r is $\pink{\bf \dfrac{1}{2}}$.