( 8 )sin (45° + A) - cos (45° - A)
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Answer:
We know that
{sin(90-\theta)= cos\theta}
sin(90−θ)=cosθ
Here,
sin(45+A) - cos(45-A)
= sin(45+A)-sin[90-(45-A)]
= sin(45+A) - sin(90-46+A)
= sin(45+A)-sin(45+A)
= 0
Therefore,
Value of sin(45+A)-cos(45-A)=0
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