Question

( 8 )sin (45° + A) - cos (45° - A)​

Answer 1

Answer:

We know that

{sin(90-\theta)= cos\theta}

sin(90−θ)=cosθ

Here,

sin(45+A) - cos(45-A)

= sin(45+A)-sin[90-(45-A)]

= sin(45+A) - sin(90-46+A)

= sin(45+A)-sin(45+A)

= 0

Therefore,

Value of sin(45+A)-cos(45-A)=0