8(sin^6theta+cos^6theta)-12(sin^4theta+cos4theta)
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hey friends !!!
=8( sin^6¢+ cos^6¢)-12 (sin⁴¢+cos²¢)
=8{(sin²)³+( cos²)³}-12{(sin²¢)²+(cos²¢)²}
=8{(sin²¢+cos²¢)(sin⁴¢+cos⁴¢-sin²¢×cos²¢)}-12{(sin²¢+cos²¢)²-2sin²¢×cos²¢)}
=8{(1) ( sin²¢)²+(cos²¢)²-sin²¢×cos²¢)}-12(sin²¢+cos²¢)²-2sin²¢×cos²¢)
=8{(sin²¢+cos²¢)²-2 sin²¢×cos²¢-sin²¢×cos²¢}-12{(sin²¢)²+(cos²¢)²-2sin²¢×cos²¢
=8{(1-3sin²¢×cos²¢)}-12{1-2sin²¢×cos²¢}
=8-24cos²¢×sin²¢-12+24sin²¢×cos²¢
=-4 Answer. ...
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hope it helps you !!
.#rajukumar
=8( sin^6¢+ cos^6¢)-12 (sin⁴¢+cos²¢)
=8{(sin²)³+( cos²)³}-12{(sin²¢)²+(cos²¢)²}
=8{(sin²¢+cos²¢)(sin⁴¢+cos⁴¢-sin²¢×cos²¢)}-12{(sin²¢+cos²¢)²-2sin²¢×cos²¢)}
=8{(1) ( sin²¢)²+(cos²¢)²-sin²¢×cos²¢)}-12(sin²¢+cos²¢)²-2sin²¢×cos²¢)
=8{(sin²¢+cos²¢)²-2 sin²¢×cos²¢-sin²¢×cos²¢}-12{(sin²¢)²+(cos²¢)²-2sin²¢×cos²¢
=8{(1-3sin²¢×cos²¢)}-12{1-2sin²¢×cos²¢}
=8-24cos²¢×sin²¢-12+24sin²¢×cos²¢
=-4 Answer. ...
~~~~~~~~~~~~~~~~~~
hope it helps you !!
.#rajukumar
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