Math, asked by amritasingh2835, 4 months ago

8. Solve the inequation 3x + 5 > x-9, if the values of x are the negative integers.
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Answers

Answered by Athalia
6

Answer:

3x + 5 = x-9

Step-by-step explanation:

Subtract 5 from both side of the equation.

3x+5-5=x-9-5

Simplify

Subtract the numbers.

3x = x - 14

Subtract x from both the sides of the equation.

3x-x = x-14-x

Simplify

Combine like numbers

2x = -14

Divide both the side of the equation by the same term

2x = -14

2 2

Simplify

Cancel terms that are both numerator and denominatior

Divide the numbers.

x = -7

Solution - x = -7

Answered by khirwarshourya
6

Answer:

3x + 5 = x-9

Step-by-step explanation:

Subtract 5 from both side of the equation.

3x+5-5=x-9-5

Simplify

Subtract the numbers.

3x = x - 14

Subtract x from both the sides of the equation.

3x-x = x-14-x

Simplify

Combine like numbers

2x = -14

Divide both the side of the equation by the same term

2x = -14

2 2

Simplify

Cancel terms that are both numerator and denominatior

Divide the numbers.

x = -7

Solution - x = -7

all the best for your exam baby

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