Question

8 spherical rain drops of equal size are falling vertically through air with a terminal velocity of 0.1m/s .What should be the velocity if there drops were combine to form one large spherical drop.

Answer 1

$8*(4/3)\pi r^{3}  = (4/3)\pi R^{3}$

Solving,

we get, R=2r

Now terminal speed is directly proportional to the square of the radius. Thus

$v_{1} /v_{2} = r^{2}/R^{2}$

Substituting the values,

$0.1/v_2=r^2/2r\\v_2=4*0.1\\ Therefore,\\v_2= 0.4 m/s^2$

Answer 2

Answer:

ta uhghhh gh

Explanation:

this is the answer of your question