Question

8. Subtract the sum of 4a - 2b + 3c – 9 and
-3b + 4c from the sum of 6b - 6c + 12 and
a-b+c-4.​

Answer 1

Answer:

the answer is as follows

Step-by-step explanation:

(6b-6c+12+a-b+c-4)-(4a-2b+3c-9-3b+4c)

= (5b - 5c +8 + a )- ( 4a -5b +7c - 9 )

= (5b - 5c + 8 + a) - 4a +5b -7c +9

=  10b +17 - 3a

Answer 2

Answer:-

The required answer is - 3a - 14c + 17

Step-by-step explanation:-

Given that,

Subtract the sum of 4a - 2b + 3c – 9 and -3b + 4c from the sum of 6b - 6c + 12 and a-b+c-4

Solution:-

Accordingly,

Given that, first let's find the sum, then subtract,

( 4a - 2b + 3c – 9 ) + ( - 3b + 4c ) ... equation 1

➝ 4a - 5b + 7c - 9

( 6b - 6c + 12 ) + ( a - b + c - 4 ) .... equation 2

➝ a - 5b - 7c + 8

Now, subtracting equation 1 from equation 2,

( 4a - 5b + 7c - 9 ) from ( a - 5b - 7c + 8 )

➝ ( a - 5b - 7c + 8 ) – ( 4a - 5b + 7c - 9 )

➝ - 3a - 14c + 17