8 taps having the same rate of flow , fill a tank in 27 minutes . if two taps go out of order , how long will the remaining taps take to fill the tank
Answers
Answered by
8
given that 8 similar taps can fill a tank in 27min
then 1 tap can fill a tank in 27/8min
if 2 taps go out of order then there will be 6taps which fills the tank
if 1tap fill it in 27/8min then 6taps can fill it in
6*27/8 min
=81/4 min
=20.25 min
then 1 tap can fill a tank in 27/8min
if 2 taps go out of order then there will be 6taps which fills the tank
if 1tap fill it in 27/8min then 6taps can fill it in
6*27/8 min
=81/4 min
=20.25 min
hindusha:
thank u and nice
Answered by
24
here is your answer
Total no of taps=8
No of tap goes out of order=2
Remaining no of taps=(8-2)=6
1 tap fills the tank in =(27×8) minutes
6 taps can fill the tank in(27×8)/6
=36 minutes
Total no of taps=8
No of tap goes out of order=2
Remaining no of taps=(8-2)=6
1 tap fills the tank in =(27×8) minutes
6 taps can fill the tank in(27×8)/6
=36 minutes
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