Question

8. The area of a triangle whose sides are 7cm, 9cm and 14cm is
12root5cm^2
12 root 3cm^2
24 root 50^2
63cm^2​

Answer 1

Answer:

Area of triangle = S(S−a)(S−b)(S−c)

S=2a+b+c

Given a=7 cm

b=9 cm

c=14 cm

S=27+9+14

=230

S=15cm

∴ Area of triangle = S(S−a)(S−b)(S−c)

=15(15−7)(15−9)(15−14)

=15.8.6.1

=720

=3×144

=12×12×5

=125cm2

∴ Area of triangle = 12.5 cm2

So, the answer is A. 12.5 cm2

Answer 2

$\bf\underline{\underline{\green{SOLUTION:-}}}$

Question

• The area of a triangle whose sides are 7cm, 9cm and 14cm is?

Answer

• Area of triangle is 12√5cm²

Given

• Sides are :- 7cm, 9cm and 14cm

To Calculate

• Area of triangle __?

Explanation

Sides are 7cm , 9cm and 14cm

Semi perimeter = a+b+c /2

↝ 7+9+14 /2

↝ 30/2

↝ 15cm

☆ Using Heron's formula ☆

$Area \: of \: triangle = \sqrt{s(s - a)(s -b)(s - c)}$

Putting values,

$⟹ \sqrt{15(15 - 7)(15 - 9)(15 - 14)}$

$⟹ \: \sqrt{15 \times 8 \times 6 \times 1}$

$⟹ \sqrt{720}$

$⟹\sqrt{3 \times 144}$

$⟹ \sqrt{12 \times 12 \times 5}$

$⟹12 \sqrt{5} cm ^{2}$

$\bf\underline{\underline{\green{HENCE:-}}}$

• Area of triangle is 12√5cm²

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