Math, asked by 8878, 1 month ago

8. The base and height of a triangle are in the ratio 2:3 and its area is 48 cm Find its base and height.

Answers

Answered by smosan75

32

Let the base and height be 2x and 3x respectively.,Then,

1/2 × 2x × 3x=48

=>6x²=48×2

=>6x²=96

=>x²=96/6

=>x=root 16

=>x=4

Therefore,

BASE=(2×4)cm=8cm

HEIGHT=(3×4)cm=12cm

PLEASE MARK ME BRAINLIEST.

Previous Question

Next Question

Similar questions

Hindi, 23 days ago

डेंगू से बचाव के लिए हमें क्या करना चाहिए...

English, 23 days ago

Q.2 SEEN PASSAGE. 05 Students! You must have seen the picture of an old lady, hardly five feet tall, with high cheek – bones, thin lips and a wrinked face, clad in a white saree with a blue border covering the head. This is Mother Teresa often called ‘The Gentle Mother’ or the ‘Angel of Mercy.’ Mother Teresa was born in Skopje, Macedonia on August 27, 1910. Her family was of Albanian...

Science, 23 days ago

why do organism take a food processor...

English, 1 month ago

1 Understanding the Story A Answer the following questions briefly: 1. W did the young man go to the remote sea? 2. Why did the elder brothers become jealous of their youngest brother? 3. How did the young man save the buck and the jackal? 4. What proclamation had the princess of the strange palace made? 5. How did the three animals—the fish, the buck and the jackal, repay the kindness of the...

English, 1 month ago

" These beautiful green apples from my neighbour's orchard " is which type of phrase ?? The one who answers correctly and without scams will be marked brainiest. The one who spams will be reported.

Science, 8 months ago

HOW IS BURNING OF LPG GAS BOTH PHYSICAL AND CHEMICAL CHANGE? PLS USE THE WORD "EXOTHERMIC REACTION" (ONE WITH RELEVANT WILL BE MARKED AS BRAINLIEST )...

Math, 8 months ago

Let $A=\left[\begin{array}{ccc}1&sin\theta&1\\-sin\theta&1&sin\theta\\-1&-sin\theta&1\end{array}\right]$ , where 0 ≤ θ ≤ 2π. Then A. Det (A) = 0 B. Det (A) є (2, [infinity]) C. Det (A) є (2, 4) D. Det (A) є [2, 4]...

Math, 8 months ago

Prove that $\left\begin{vmatrix}x &x^{2} &1+px^{3} \\y&y^{2}&1+py^{3} \\z&z^{2} &1+pz^{3} \end{vmatrix}\right=(1-pxyz)(x-y)(y-z)(z-x)$ where p is any scalar.