Question

8.
The height of a cone is 6m and the diameter of its base is 16m. Find its
i) Slant height.
ii)Curved surface area ( C.S.a ).
iii)Total surface area ( T.S.A ).
iv)Volume.

answer fast​

Answer 1

QUESTION

The height of a cone is 6m and the diameter of its base is 16m.

1. Slant height

2. CSA

3.TSA

4.volume

Provided data

h = 6 m

diameter = 16 m

radius = 8 m

1 . slant height =√[ radius^2 + height ^2]

= √[8 ^2 + 6 ^2]

= √ 100

= 10 m

2. CSA = π r l

= 3.14 × 8 × 10

= 251.32 m^2

3.TSA = πrl + πr^2

= 3.14 × 8 ( 10 + 8)

= 452.4 m^2

4. Volume = 1/3 πr^2h

= 1/3 3.14 × 8^2 × 6

= 402.12 m^3

Answer 2

GivEn:

• Height of cone, h = 6 m
• Diameter of cone, d = 16 m

To find:

• Slant height
• Curved surface area
• Total surface area
• Volume of cone

Solution:

i) Slant height of cone

• Let slant height of cone be l cm.

We know that,

Slant height = √(radius)² + (height)²

⇒ l = √r² + h²

⇒ l = √8² + 6²

⇒ l = √64 + 36

⇒ l = √100

⇒ l = 10 m

Hence, Slant height of cone is 10 m.

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━

ii) Curved surface area of cone

We know that,

• CSA of cone = πrl

Here,

• r = 8 m
• l = 6 m

Putting values,

⇒ 22/7 × 8 × 10

⇒ 251.42 m²

Hence, CSA of cone is 251.42 m²

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━

iii) Total surface area of cone

We know that,

• TSA of cone = πrl + πr²

⇒ 251.42 + 22/7 × (8)²

⇒ 201.14 + 251.42

⇒ 452.56 m² (approx)

Hence, TSA of cone is 452.56 m².

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━

iv) Volume of cone

We know that,

• Volume of cone = 1/3 πr²h

Here,

• r = 8 m
• h = 6 m

Therefore,

⇒ 1/3 × 22/7 × 8² × 6

⇒ 1/3 × 22/7 × 64 × 6

⇒ 22/7 × 128

⇒ 402.28 m³ (approx)

Hence, Volume of cone is 402.28 m³