Question

8) The number of polynomials having Zeroes. as -2 and 5 is
a) 1
(b) 2
(c) 3
(d) more than 3​

Answer 1

Answer:

Let p(x)=ax2+bx+c be the required polynomial whose zeroes are -2 and 5. But we know that, if we multiply/divide any polynomial by any arbitary constant. Then, the zeroes of polynomial never change. Hence, the required number of polynomials are infinite i.e., more than 3.

HOPE IT HELPS YOU

Answer 2

Zeroes of polynomial =-2 and 5

P (x)= ax square +bx +c

Sum of zeroes = -( coefficients of x ) ÷ coefficients of x squares

Sum of zeroes =-b/a

-2+5=-b/a

3=-b/ a

b=-3 and a =1 .

product of zeroes = constant term ÷ coefficients of x squares

Product of zeroes =-c/a

-10=c

substituting a,b,c, in polynomial we get

x square -3x-10.

Hope it helps u

Mark it as BRAINLIEAST please i request