8) The number of polynomials having Zeroes. as -2 and 5 is
a) 1
(b) 2
(c) 3
(d) more than 3
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0
Answer:
Let p(x)=ax2+bx+c be the required polynomial whose zeroes are -2 and 5. But we know that, if we multiply/divide any polynomial by any arbitary constant. Then, the zeroes of polynomial never change. Hence, the required number of polynomials are infinite i.e., more than 3.
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Answered by
19
Zeroes of polynomial =-2 and 5
P (x)= ax square +bx +c
Sum of zeroes = -( coefficients of x ) ÷ coefficients of x squares
Sum of zeroes =-b/a
-2+5=-b/a
3=-b/ a
b=-3 and a =1 .
product of zeroes = constant term ÷ coefficients of x squares
Product of zeroes =-c/a
-10=c
substituting a,b,c, in polynomial we get
x square -3x-10.
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