Chemistry, asked by ssudhakarreddy201, 4 months ago

8. The rate constant for the reaction
2N,02 +4NO, + O2, is 3.0 x 10-5 sec-1. If the
rate is 2.40 x 10-5 mol lit-1 sec-1 then the
concentration of N 05 (in mol litre-l) is
1. 1.4 2.1.2 3. 0.8 4. 0.04​

Answers

Answered by itzBrainlymaster
4

The given reaction is:

2N

2

O

5

⟶4NO

2

+O

2

The unit of rate constant indicates its first-order reaction.

Rate=K[N

2

O

5

] (Rate Law)

where K= Rate constant

Given that,

K=3×10

−5

sec

−1

Rate=2.4×10

−5

molL

−1

s

−1

Putting the given values in rate law:-

2.4×10

−5

=3.0×10

−5

[N

2

O

5

]

10

8

=[N

2

O

5

]

⇒[N

2

O

5

]=0.8 molL

−1

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