8. The rate constant for the reaction
2N,02 +4NO, + O2, is 3.0 x 10-5 sec-1. If the
rate is 2.40 x 10-5 mol lit-1 sec-1 then the
concentration of N 05 (in mol litre-l) is
1. 1.4 2.1.2 3. 0.8 4. 0.04
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The given reaction is:
2N
2
O
5
⟶4NO
2
+O
2
The unit of rate constant indicates its first-order reaction.
Rate=K[N
2
O
5
] (Rate Law)
where K= Rate constant
Given that,
K=3×10
−5
sec
−1
Rate=2.4×10
−5
molL
−1
s
−1
Putting the given values in rate law:-
2.4×10
−5
=3.0×10
−5
[N
2
O
5
]
⇒
10
8
=[N
2
O
5
]
⇒[N
2
O
5
]=0.8 molL
−1
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