8. The total current in a tree-branch parallel circuit is 500mA. If 207mA of current is flowing through one branch, and 153mA through another, what would be the current through the third branch?
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Total current = 500mA
I1=207mA
I2=153mA
I3=?
I3=I-(I1+I2)
=500-(207+153)
=500-360
=140mA
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I1=207mA
I2=153mA
I3=?
I3=I-(I1+I2)
=500-(207+153)
=500-360
=140mA
Hope this helps you
Mark me as the brainiest
Also follow me
Also give this solution a 5 star and thanks
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