Math, asked by nonu110207, 11 months ago

8) The total strength of the class is 90 and the number of girls is twice that of
boys. Suraj is ranked 14th from the top. Suppose there are 10 girls ahead of Suraj.
Find the number of boys after Suraj in the ranking order.

Answers

Answered by ansh1333
16

Answer:

there are 26 boys behind suraj

Step-by-step explanation:

solution

let boys be x and girls 2x

total students =90

x+2x=90

3x=90

x=30

boys=30

girls=60

assuming that 10 girls are ahead of suraj and he is at 14 rank so there are 4 boys within 14 rank including Suraj

so total boys after Suraj =30-4=26

Answered by ankhidassarma9
1

Answer:

There are 26 boys after Suraj in the ranking order.

Step-by-step explanation:

  • Total number of Student in the class is 90.
  • Let the number of boys in the class be x.

so, the number of girls in the class is twice of x ,i.e. 2x.

  • no. of boys + no. of girls = Total no. of students

so, we can write x + 2x = 90

                    hence x = 30 and 2x = 60

The number of boys in the class is 30.

The number of girls in the class is 60.

  • Suraj is ranked 14th from the top. If there are 10 girls ahead of Suraj then there must be 3 boys ahead of Suraj so that Suraj can hold 14th position.
  • Hence, till 14th position 4 boys (including Suraj) are there.

so, number of boys after Suraj = 30 - 4 =26.

  • The number of boys after Suraj in the ranking order is 26.

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