Math, asked by devidivyas2020, 22 days ago

8.

The value of x and y in equations 217x + 131y = 913 and 131x + 217y + 827 is
a) 2, 3
b) 4.2
c) 3,2
d) 5,4

Answers

Answered by arpitmallick
1

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Answered by tennetiraj86
1

Option -C

Step-by-step explanation:

Correction :-

131X+217Y = 827

Given :-

217X+131Y = 913

131X+217Y = 827

To find :-

Find the values of X and Y ?

Solution:-

Given equations are :-

217X+131Y = 913 ------------(1)

131X+217Y = 827 ------------(2)

On adding (1)&(2) then

217X+131Y = 913

131X+217Y = 827

(+)

________________

348X + 348Y = 1740

________________

=> 348X + 348Y = 1740

=> 348(X+Y) = 1740

=> X+Y = 1740/348

=> X+Y = 5 -----------------(3)

On Subtracting (2) from (1)

217X+131Y = 913

131X+217Y = 827

(-)

________________

86X -86Y = 86

________________

=> 86X -86Y = 86

=> 86(X-Y) = 86

=>X-Y = 86/86

=> X-Y = 1 ------------------(4)

On adding (3)&(4)

X+Y = 5

X-Y = 1

(+)

________

2X+0 = 6

________

=> 2X = 6

=> X = 6/2

=> X = 3

On Substituting the value of X in (3) then

=> 3+Y = 5

=> Y = 5-3

=> Y = 2

Therefore, X = 3 and Y = 2

Answer:-

The value of X = 3

The value of Y = 2

Check:-

If X = 3, Y = 2 then

LHS of (1)

=> 217(3)+131(2)

=> 641+262

=>913

=> RHS

LHS = RHS is true for X and Y

LHS of (2)

=> 131(3)+217(2)

=>393+434

=>827

=> RHS

LHS = RHS is true for X = 3 and Y = 2

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