Question

8. Three bells ring at intervals of 15 s, 21s
and 16 s, respectively. All bells ring
simultaneously at 12:00 noon. They will
again ring simultaneously at
(1) 28 min past 12
(2) 25 min past 12
(3) 26 min past 12
(4) 24 min past 12​

Answer 1

Step-by-step explanation:

28 min past 12

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Answer 2

Answer:

28 min past 12

Step-by-step explanation:

Required time to ring again = LCM of 15,21 and 16

Now, 15 = 3×5; 21= 3×7

16 = 2×2×2×2

Therefore LCM = 3×5×7×2×2×2×2

= 1680 s = 28 min

Clearly, all the bell will ring at 28 min past 12.