8. Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of octagonal surface.4cm
Answers
Solution;
Solution;Figure is in the attachment...
Solution;Figure is in the attachment...Given:
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55 Area of Rectangle = 55 m²
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55 Area of Rectangle = 55 m²Total area of octagon = 64 + 55= 119
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55 Area of Rectangle = 55 m²Total area of octagon = 64 + 55= 119
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55 Area of Rectangle = 55 m²Total area of octagon = 64 + 55= 119 Total area of octagon = 119 m²
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55 Area of Rectangle = 55 m²Total area of octagon = 64 + 55= 119 Total area of octagon = 119 m²==========================================================
Solution;Figure is in the attachment...Given: Sides of octagon= 5 m.Area of Trapezium= (1/2) × (Sum of parallel sides) × Perpendicular distance= (1/2) (11+5)4= 16 x 2= 32m²Area of 2 trapeziums = 64 m²Area of Rectangle = Length x Breadth= 11 x 5 = 55 Area of Rectangle = 55 m²Total area of octagon = 64 + 55= 119 Total area of octagon = 119 m²==========================================================Hope this will help you...
Hope it helps you.................
