Question

8. Total elastic potential energy stored in a stretched wire of length 1, cross-sectional area A and Young's modulus Y fixed at one end is [NCERT Pg. 244] (1) 1 Stress 2 Strain * Volume (2) 1 x Stress x Strain 2 (3) NI- 1 * Stress Strain * Volume x x 2. (4) 2 x(Strain)? x Volume ​

Answer 1

Answer:

1/2 x stress x strain x volume is the answer

Explanation:

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