8) Two circles of radil 8 cm and 6 cm intersect at two points and the distance between their centres is 10 cm. Find the length of the common chord.
Answers
Answered by
1
Answer:
ans 4cm
Step-by-step explanation:
If circles were just touching
distance between centres = sum of there radius
which = 14 cm
but given that there centres are 10 cm apart
so length of common chord = distance between centres if they were just touching subtracted by given distance
that is equals to 14 - 10 = 4 cm
Answered by
2
Answer:
12cm
Step-by-step explanation:
r=8cm R=6cm d=10cm
length of a common chord =?
when measured chord cd=12
circles with center a and b, interest at point c an d
CD is common
perpendicular bisector of CD is ab
ac = 8cm
bc = 6cm
chord cd =2×oc
2×6
chord cd=12cm
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