Math, asked by ag921265ayush, 1 month ago

8. Two numbers are such that the ratio between them is 3:5. If each is increased
by 10, the ratio between new numbers so formed is 5:7. Find the smallest
original number
A. 15
B. 11
C. 7
D. 5​

Answers

Answered by Anonymous
48

Answer:

Given :-

  • Two numbers are such that the ratio between them is 3 : 5.
  • If each is increased by 10, the ratio between new numbers so formed is 5 : 7.

To Find :-

  • What is the smallest original number.

Solution :-

Let,

\mapsto \bf{First\: Number =\: 3x}

\mapsto \bf{Second\: Number =\: 5x}

10 is increased in both the numbers :

\leadsto \sf First\: Number =\: 3x + 10

\leadsto \sf Second\: Number =\: 5x + 10

According to the question,

\implies \bf (3x + 10) : (5x + 10) =\: 5 : 7

\implies \sf \dfrac{3x + 10}{5x + 10} =\: \dfrac{5}{7}

By doing cross multiplication we get,

\implies \sf 5(5x + 10) =\: 7(3x + 10)

\implies \sf 25x + 50 =\: 21x + 70

\implies \sf 25x - 21x =\: 70 - 50

\implies \sf 4x =\: 20

\implies \sf x =\: \dfrac{20}{4}

\implies \sf\bold{\purple{x =\: 5}}

Hence, the required numbers are :

First Number :

\longrightarrow \sf First\: Number =\: 3x

\longrightarrow \sf First\: Number =\: 3 \times 5

\longrightarrow \sf\bold{\red{First\: Number =\: 15}}

Second Number :

\longrightarrow \sf Second\: Number =\: 5x

\longrightarrow \sf Second\: Number =\: 5 \times 5

\longrightarrow \sf\bold{\red{Second\: Number =\: 25}}

{\small{\bold{\underline{\therefore\: The\: smallest\: original\: number\: is\: 15\: .}}}}

Hence, the correct options is option no (A) 15.

Answered by rohithkrhoypuc1
21

Step-by-step explanation:

\underline{\purple{\ddot{\Mathsdude}}}

To prove :-

  • The smallest original number.

Explanation :-

  • Let ,
  • First number should be 3 x
  • Second number should be 5x

♧♧Here 10 is increased in both of the numbers.

  • Then numbers be
  1. First number should be =3x+1
  2. Second number should be =5x+10

♧♧According to the given question :-

  • (3x+10) : (5x+10)=5:7

  • 3x+10/5x+10=5/7

♧♧Now by doing cross multiplication we get

  • 5(5x+10) = 7 (3x+10)

  • 25x+50 =21x +70

  • 25x -21 x = 70-50

  • 4x = 20

  • x =20/4

  • x = 5

Hence here required numbers are:-

  • First number =3x

=3×5

  • =15

  • Second number =5x

=5×5

=25.

Therefore, the smallest original number is 15.

Hope it helps u mate .

Thank you .

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