8. Two numbers are such that the ratio between them is 3:5. If each is increased
by 10, the ratio between new numbers so formed is 5:7. Find the smallest
original number
A. 15
B. 11
C. 7
D. 5
Answers
Answered by
48
Answer:
Given :-
- Two numbers are such that the ratio between them is 3 : 5.
- If each is increased by 10, the ratio between new numbers so formed is 5 : 7.
To Find :-
- What is the smallest original number.
Solution :-
Let,
➦ 10 is increased in both the numbers :
According to the question,
By doing cross multiplication we get,
Hence, the required numbers are :
❒ First Number :
❒ Second Number :
Hence, the correct options is option no (A) 15.
Answered by
21
Step-by-step explanation:
To prove :-
- The smallest original number.
Explanation :-
- Let ,
- First number should be 3 x
- Second number should be 5x
♧♧Here 10 is increased in both of the numbers.
- Then numbers be
- First number should be =3x+1
- Second number should be =5x+10
♧♧According to the given question :-
- (3x+10) : (5x+10)=5:7
- 3x+10/5x+10=5/7
♧♧Now by doing cross multiplication we get
- 5(5x+10) = 7 (3x+10)
- 25x+50 =21x +70
- 25x -21 x = 70-50
- 4x = 20
- x =20/4
- x = 5
♧♧Hence here required numbers are:-
- First number =3x
=3×5
- =15
- Second number =5x
=5×5
=25.
♧♧Therefore, the smallest original number is 15.
♧♧Hope it helps u mate .
♧♧Thank you .
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