Math, asked by muskansran1, 2 months ago

plz give correct answer for the above question​

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Answers

Answered by adityatatte10
0

Answer:

option 3rd is correct answer.

Answered by Anonymous
7

\boxed{ \underline{ \underline{\footnotesize\tt{ \: Solution:-} }}}\:  \purple{\: ♬}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

  \purple \leadsto\footnotesize \tt{4 \times 81 ^{ \frac{ - 1}{2} } (81^{ \frac{1}{2} }  + 81  ^{ \frac{3}{2} })}

  \purple \leadsto \footnotesize \tt{4 \times ({9}^{2})  ^{ \frac{ - 1}{2} } (( {9}^{2}) ^{ \frac{1}{2} }  +  ({9}^{2} ) ^{ \frac{3}{2} })}

  \purple \leadsto \footnotesize \tt{4 \times ({9}^{ \cancel2})  ^{ \frac{ - 1}{ \cancel2} } (( {9}^{ \cancel2}) ^{ \frac{1}{ \cancel2} }  +  ({9}^{ \cancel2} ) ^{ \frac{3}{ \cancel2} })}

  \purple \leadsto \footnotesize \tt{4 \times  {9}^{ - 1}   (9 +  { {9}^{3} } )}

  \purple \leadsto \footnotesize \tt{4 \times  \frac{1}{9}    (9 +  { {9}^{3} } )}

  \purple\leadsto \footnotesize \tt{4 \times  \frac{1}{9}    (9 +  729)}

  \purple \leadsto \footnotesize \tt{4 \times  \frac{1}{9} ( 738)}

  \purple \leadsto \footnotesize \tt{4 \times  \frac{1}{ \cancel9}  \times \cancel{  738 }}

  \purple\leadsto \footnotesize \tt{4 \times82}

\boxed{ \underline{ \underline{ \purple \leadsto\footnotesize\tt{ 328} }}}\:  \purple{\: ♬}

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