8 women and 12 men can together finish an embroidery work in 10 days, while 6 women and 8 men can finish it in 14 days. Find the time taken by 1 woman alone to finish the work, and also that taken by 1
man alone.
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Given:
- 8 women and 12 men can together finish an embroidery work in 10 days
- 6 women and 8 men can finish it in 14 days
To find:
Time taken by 1 woman alone and 1 man alone to complete the task
Solution:
As per the data given in the question:
- (8W+12M)10 = (6W+8M)14
- 40W+60M = 42W+56M
- 4M = 2W
- 2M = W -----------(I)
Time taken by 1 woman
Let work will be finished in D days.
- (8W+12M)10 = (W)D
from equation (I)
- (8W + 6W)10 = WD
- (14W)10 = WD
- 140W = WD
- D = 140
Time taken by 1 man:
Let work will be finished in D' days.
- (8W+12M)10 = (M)D'
from equation (I)
- (16M + 12M)10 = MD'
- (28M)10 = MD'
- 280M= MD'
- D' = 280
Time taken by 1 woman alone and 1 man alone to complete the task is 140 days and 280 days respectively.
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