8(x-2)²=(2x-1)²+3 quadractic equation
Answers
Answered by
1
8(x^2-4x+4)=4x^2-4x+1+3
8x^2-32x+32-4x^2+4x-4=0
4x^2-28x+28=0
Divide by 4
X^2-7x+7=0
D= b^2-4ac = 49-28 =21
X= (-b-+square root D)/4a
(7_+sq root 21)/2
8x^2-32x+32-4x^2+4x-4=0
4x^2-28x+28=0
Divide by 4
X^2-7x+7=0
D= b^2-4ac = 49-28 =21
X= (-b-+square root D)/4a
(7_+sq root 21)/2
Answered by
2
Answer:
x=root31/2
Step-by-step explanation:
8(x-2)²=(2x-1)²+3
8( x² +4 - 4x) = 4x² + 2- 4x + 3
8( x² +4) = 4x²+ 5
8x² + 36 = 4x² +5
8x² - 4x² =5 - 36
4x² = -31
x² = 31/4
x= root31/2
Similar questions