Question

8/(x+3)-3/(2-x)
pls answer fast​

Answer 1

Answer:

$\implies \frac {8}{(x+3)}- \frac {3}{(2-x)} \\ \implies \frac {8(2-x) - 3(x+3)}{(x+3)(2-x)} \\ \implies \frac {16 - 8x -3x - 9}{2x + 6 - x^2 -3x} \\ \implies\frac {7-11x}{-x^2-x+6}\\\implies\frac {11x-7}{x^2+x-6}\\ \implies\frac {11x-7}{x^2+(3-2)x-6}\\ \implies\frac {11x-7}{x^2+3x-2x-6} \\ \implies \frac {11x-7}{x(x+3)-2(x+3)} \\ \implies\frac {11x-7}{(x-2)(x+3)}$