Question

solve the equation x+y=5andx-y=1 by substituting method

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Answer 1

Answer:

x = 3, y = 2

Step-by-step explanation:

We have,

x + y = 5 ----- 1

x - y = 1 ------ 2

From eq.2 we get,

x = 1 + y ------ 3

Substituting eq.3 in eq.1 we get,

x + y = 5

(1 + y) + y = 5

1 + 2y = 5

2y = 5 - 1

2y = 4

y = 4/2

y = 2

Putting y = 2 in eq.3,

x = 1 + y

x = 1 + 2

x = 3

Hence,

x = 3, y = 2

Hope it helped and believing you understood it. All the best.

Answer 2

Answer :

➪ $x = \bf 3$

➪ $y = \bf 2$

Explanation :

Given equation :

➪ $x + y = 5\bf ------ (i)$

➪ $x - y = 1 \bf ------- (ii)$

${\underline{\rm{Solving \: for \: }}x : }$

Equation (i) :

$\implies x + y = 5$

$\implies y = 5 + x$

Now, substituting the value of $y$ in equation (ii) :

$\implies x - y = 1$

$\implies x - 5 + x = 1$

$\implies 2x - 5 = 1$

$\implies 2x = 5 + 1$

$\implies 2x = 6$

$\implies x = \dfrac{6}{2}$

$\implies x =\bf 3$

Again, substituting the value of $x$ in equation (i) :

$\implies x + y = 5$

$\implies 3 + y = 5$

$\implies y = 5 - 3$

$\implies y = \bf 2$

Hence,

➪ $x = 3$

➪ $y = 2$