80 coins of 10 paise and 50 paise are mixed in a purse. if the value of the money in the purse is rupees 24 find the number of each type of coin s.
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let the number of 10 paisa be x and 50 paisa =(80-x)
a/q
10x+50(80-x)=2400
or, 10x+ 4000-50x= 2400
or, -40x = -1600
or, x = 40
hence number of 10 paisa coin 40
and 80 paisa coin 80-40= 40
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