Question

80 g of H2 is reacted with 80 g of O2 to form water. find out the mass of water obtained.which substance is the limiting reagent?

Answer 1

hope it was helpful to you

Answer 2

Dear student;

2H2 + O2 ⇒ 2H2O
4g       32g     36g
80g      80g      ? 

∵4 g H2 requiresO2 = 32g
∴ 80 g H2 will require O2 =640 g, but available O2 is only 80 g .Thus limiting reagent is O2.
Now,
 ∵32g O2 gives water = 36g
∴80g O2 will give water = 90g

thus mass of water obtained is 90g.