Question

80 gram of h2 are reacted with 80 gram of o2 to form water find out the mass of water obtained which substance is the limiting reagent

Answer 1

H2+O2-----> H2O

mass of water = 80+80 = 160g

generally,

2g of H2 = 32g of O2

so, 80g of H2= 32*80/2

=1280g of oxygen is required but only 80g is present

so oxygen is the limiting reagent