Question

80. If there are two de-Broglie waves formed in an orbit
of H-atom then the energy of electron in that orbit is
(1) -3.4 eV
(2) -13.6 eV
(3) -9.06 eV
(4) 1.51 eV​

Answer 1

due to charge of electron which is most of the least value

Answer 2

The energy of electron in orbit of hydrogen is, -3.4 eV

Explanation :

Formula used to calculate the energy of electron in orbit of hydrogen is:

$E=-13.6\times \frac{z^2}{n^2}$

where,

E = energy of electron in orbit of hydrogen

z = atomic number of hydrogen = 1

n = number of orbit = 2

Now put all the given values in the above formula, we get:

$E=-13.6\times \frac{(1)^2}{(2)^2}$

$E=-3.4eV$

Therefore, the energy of electron in orbit of hydrogen is, -3.4 eV

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