Question

80 men complete a piece of work in 64 days. if 80 men do the work in 36 days then work complete before 2 days.

Answer 1

Hey mate!

Here's your answer!!

Note: Your question is incomplete so I'm answering by assuming the values.

Work done by 80 men in 36 days + Work done by 100 men in (64−2−36)=26 days =1

Suppose 1 man does 1 unit of work in 1day. Then, total work =80×36+100×26=5480 units.

Suppose, 20 more men were not employed and 80men complete the work in n days 80 n=5480 n = 68.5

Therefore, work would have delayed by
(68.5−64)= 4.5 days

$hope \: it \: helps \: you.$
✌ ✌

#BE BRAINLY