80 ml of uncombined oxygen in meaning of exploding oxygen with 4 ml of hydrogen then number of ml of oxygen originally where
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Dear Student,
As, 2H2 + O2 → 2H2O
So, 2 moles of hydrogen react with one mole of oxygen to form 2 moles of water.
By Gay-Lussac’s law,
1 mL of oxygen reacts with every 2 mL of hydrogen.
So, 2 mL of oxygen react with 4 mL of hydrogen.
Therefore, VO2(original)=VO2(remaining)+VO2(reacted)
Hence, VO2(original)=8+2=10 mL
I hope it helps you✔❤
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