Question

80 points please solve

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Answer 1

Answer:

7, Angle ACB & angle ACD are linear pair . Hence <ACB + <ACD = 180°

Given <ACB = 100°

i) Hence <ACD = 180° - 100° = 80°

Total sum of angles in a triangle = 180°

<ABC + <BCA + <BAC = 180°

40° + 100°+ <BAC =180°

ii) <BAC = 180° - 140° = 40°

<ACD + <ADC + <CAD = 180°

80° + <ADC + 40° = 180°

iii) <ADC = 180° - 120° = 60°

Answer 2

Answer:

In ques8 :

(i) angle ACD = 45 degree (as CD is the bisector of angle ACB.

(ii) by angle sum property :

Angle acb + angle abc+angle bca=180 degree

So, 90 degree + angle abc+ 50 degree = 180 degree

We get angle abc = 40 degree