Chemistry, asked by Anonymous, 6 months ago

80. Three particles of equal masses are placed
at the corners of an equilateral triangle, as
shown in fig. Now particle A starts with a
velocity v, towards line AB, particle B starts
with a velocity v, towards line BC and
particle C starts with velocity v, towards
line CA. The displacement of C.M. of three
particle A, B and C after time "t" will be
(given if v1 = V2 = v3)​.​

Answers

Answered by Yashrajgaradade
0

Answer:

v1x=2−v1,v1y=2−v13

v2x=v2,v2y=0

v3x=2−v33,v3y=v323

using , vcm=i^vx+j^vy

where,

Vx=3m−mv1/2+v2m−mv3/2=0

vy=

Explanation:

after writing answer draw the diagram also...

the diagram is in pic. type

plz mark me as bralint

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Answered by ItzYourHeartbeat
2

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