Math, asked by liktarang89, 22 days ago

8000 acres of land have to be partitioned in the ratio 8:7:5 what is the size of each part ?​

Answers

Answered by dasshreya121
0

Answer:160:140:100

Step-by-step explanation:

Given: ratio 8:7:5

To find : size of each part

Solution:

The land is divided into three parts and the ratio is given as 8:7:5

Let the proportionality constant be x

According to the question,

8x+7x+5x= 8000

20x=8000

x=400

therefore,

1st part= 8x= 8*20=160 acres

2nd part=7*20=140 acres

3rd part= 5*20=100 acres

Answered by malavikathilak123
1

Answer:

If 8000 acres of land have partitioned in the ratio 8:7:5, then the size of each part would be  3200 acres, 2800 acres, and 2000 acres respectively.

Step-by-step explanation:

Given that,

       total size of land = 8000 acres

        ratio of partition = 8 : 7 : 5

we have to partition 8000 acres of land among A, B, C in the ratio 8 : 7 : 5. This means that if A gets 8 portions, then B will get 7 portions and C will get 5 portions

then,

         the sum of the terms of ratio = 8+7+5 = 20

size of part A = 8000 × (8/20) = 3200 acres

size of part B = 8000 × (7/20) = 2800 acres

size of part C = 8000 × (5/20) = 2000 acres

thus the size of each part is 3200 acres, 2800 acres, and 2000 acres respectively.

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