Question

8000 kg engine pulls A train of 5 begin each of 2000 Wagon along a horizontal track if the Indian exert a force of 40000 Newton and the track of the friction of friction force of 5000 Newton and calculate the net accelerating for the acceleration of the train and the force of Wagon 1 on the 2​

Answer 1

Answer:

Here is your answer:

Explanation:

Force produced by engine = 40000 N

Frictional force = 5000 N

Net force = 40000 - 5000

                = 35000 N

Mass of all the wagons together = 2000(5)

                                                      = 10000 kg

F = ma

35000 = 10000(a)

a = 35000/10000

a = 3.5 m/s²

Net acceleration = 3.5 m/s²

Force applied by wagon 1 on wagon 2 =

as there as 3 more wagons behind wagon 2, we need to add all their masses as well

⇒ 2000(4)

 = 8000 N

F = ma

F = 8000(3.5)

F = 27000 N

Force acting by wagon 1 on wagon 2 is 27000 N

Hope this helps you!

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