Question

8000 kg engine pulls A train of 5 Wagons each of 2000 kg along a horizontal track if the Indian exert a force of 40000 Newton and the track of a frictional force of 5000 Newton then calculate the net accelerating force and acceleration of the train​

Answer 1

Explanation:

net aacelerating force =net force /total mass of wagons

Answer 2

Answer:-

Explanation:-

Force exerted by the engiene F¹ =40,000N.

Frictional force exerted by the track

F² = - 5000N.

Negative sign shows that is friction is opposite to the direction of motion.

1. Therefore,net accelerating force

F = F¹ + F²

F = 40,000 - 5000

F = 35,000N.

$\boxed{\boxed{F = 35,000N}}$

so,net accelerating force is 35,000N

2.Mass of each wagon of the train = 2000kg.

Number of wagons =5

therefore,

Mass of the train(without engine) = 2000 ×5 = 10,000kg.

Net accelerating force of the train is = ?.

F = 35,000N.

M = 10,000kg.

from,

$F = ma$

$a = \frac{F}{m}$

$a = \frac{35000}{10000}$

$a = 3.5$

$\boxed{\boxed{a=3.5 m/s^2}}$

so,the acceleration of train is 3.5m/s^2.