80g of H2 is reacted with 80g of O2 to form water .find out the mass of water obtained ?
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2H2+O2-- >2H20
Therefore, 2 moles of hydrogen react with 1mole of oxygen to give 2 moles of water.
Therefore 4 g of hydrogen + 32 grams of oxygen = 36 g of water
Therefore 80g of hydrogen = (32 x 20) = 640g of oxygen must be there but they are not.
Therefore 80 g of oxygen will react with 10g of hydrogen
Therefore, by law of conservation of mass
Mass of water obtained = (10 + 80) g
Therefore, 10 g of hydrogen reacts with 80g of oxygen to give 90g of water.
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