Question

81 * 3^x+1 - 9 * 3^x / 81 * 3^x+2 - 3 * 3^x+2

Answer 1

Step-by-step explanation:

9×81^x = 1/27^x-3 3²×3^4x = (1/3)^3(x- 3) 3^2+4x = 3^-[3(x-3)] Bases are equal. Exponents must be equal. 2+4x = -(3x-9) 2+4x = -3x+9 4x+3x = 9-2 ·

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