81 - Find the smallest number by which the given number must be multiplied to obtain a perfect cube?
Answers
Answered by
11
Hey there!
81 = 3 * 27
= 3 * 3³
So, To make the given number a perfect cube, You need to have two more 3 as part of its prime factorization.
3 * 3 = 9
The least number by which 81 be multiplied to get a perfect cube is 9
Multiplying 81 by 9 , you obtain 729
whose prime factorization has triplets of 9
729 = 9³
Therefore, The smallest number by which the given number 81 should be multiplied to obtain a perfect cube is 9
81 = 3 * 27
= 3 * 3³
So, To make the given number a perfect cube, You need to have two more 3 as part of its prime factorization.
3 * 3 = 9
The least number by which 81 be multiplied to get a perfect cube is 9
Multiplying 81 by 9 , you obtain 729
whose prime factorization has triplets of 9
729 = 9³
Therefore, The smallest number by which the given number 81 should be multiplied to obtain a perfect cube is 9
Answered by
8
HI ,
Resolving 81 into prime factors , we get
81 = 3 × 3 × 3 × 3
= ( 3 × 3 × 3 ) × 3
The Prime factor 3 does not appear
in a group of three .
So, 81 is not a perfect cube .
Hence , the smallest number by which
it is to be multiplied to make it a perfect
cube is 3 × 3 = 9
I hope this helps you.
: )
Resolving 81 into prime factors , we get
81 = 3 × 3 × 3 × 3
= ( 3 × 3 × 3 ) × 3
The Prime factor 3 does not appear
in a group of three .
So, 81 is not a perfect cube .
Hence , the smallest number by which
it is to be multiplied to make it a perfect
cube is 3 × 3 = 9
I hope this helps you.
: )
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