1715 - Find the smallest number by which the given number must be multiplied to obtain a perfect cube?
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Hi ,
Resolving 1715 into prime factors ,
we get
1715 = 5 × 7 × 7 × 7
= 5 × ( 7 × 7 × 7 )
The prime factor 5 doesn't appear
in a group of three .
So, 1715 is not a perfect cube .
Hence , the smallest number by which
it is to be multiplied to make it a
perfect cube is 5 × 5 = 25
I hope this helps you.
: )
Resolving 1715 into prime factors ,
we get
1715 = 5 × 7 × 7 × 7
= 5 × ( 7 × 7 × 7 )
The prime factor 5 doesn't appear
in a group of three .
So, 1715 is not a perfect cube .
Hence , the smallest number by which
it is to be multiplied to make it a
perfect cube is 5 × 5 = 25
I hope this helps you.
: )
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