Question

88,Find the smallest number by which the given number must be divided to obtain a perfect cube.

Answer 1

_____Question

88,Find the smallest number by which the given number must be divided to obtain a perfect cube.

____Your answer

Let's start our way of solving the answer through prime factorisation

2|88
2|44
2|22
|11


88 = 2×2×2× 11

on grouping the numbers we get

2 is only making a cubic pair

so the number must be divided by 11 to make a perfect cube.


Thank you

@Be Brainly

Answer 2

Hi ,

Resolving 88 into prime factors , we get

88 = 2 × 2 × 2 × 11

= ( 2 × 2 × 2 ) × 11

The prime factor 11 does not appear

in a group of three.

So, 88 is not a perfect cube .

Hence , the smallest number by which it

is to be divided to make it

perfect cube is 11

I hope this helps you.

: )