Question

.
81 और 237 का म.स. होगा-
(a)3
(b) 5
(c)7
(d) 11
full solution​

Answer 1

Answer:

3

Step-by-step explanation:

Given integers are 81 and 237 such that 81<237.

Applying division lemma to 81 and 237, we get

237=81×2+75

Since the remainder 75



=0. So, consider the divisor 81 and the remainder 75 arndapply division lemma to get

81=75×1+6

We consider the new divisor 75 and the new remainder 6 and apply division lemma to get

75=6×12+3

We consider the new divisor 6 and the new remainder 3 and apply division lemma to get

6=3×2+0

The remainder at this stage is zero. So, the divisor at this stage or the remainder at the earlier stage i.e. 3 is the HCF of 81 and 237.

Answer 2

Answer:

3 is divisible by both 81 and 237

Hope it's help You

Answer is (a) 3